Question

Choose the correct option:
$Zn(OH{)}_2+$___$\to ZnS{O}_4+2H_{2}O$

• A. $HCl$
• B. $H_2$
• C. $H_{2}S{O}_4$
• D. $Zn$

Answer 1

The correct option is C

$H_{2}S{O}_4$

From the products, it can be inferred that the reaction is a neutralization reaction, which includes the use of sulphuric acid as a strong acid
The reaction can be written as follows,
$Zn(OH{)}_2+H_{2}S{O}_4\to ZnS{O}_4+2H_{2}O$