Choose the correct order for the given properties.

M g S O_{4} < S r S O_{4} < B a S O_{4}

: Thermal stability order

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B e C_{2} O_{4} < C a C_{2} O_{4} < B a C_{2} O_{4}

: Solubility in water

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L i C l > N a C l > K C l

: Melting point order

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B e F_{2} > C a F_{2} > S r F_{2}

: Covalent character order

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Solution

The correct options are
A $M g S O_{4} < S r S O_{4} < B a S O_{4}$ : Thermal stability order
D $B e F_{2} > C a F_{2} > S r F_{2}$ : Covalent character order
In alkaline earth metals, as we move down the group, ionic character of fluoride increases so covalent order is $B e F_{2} > C a F_{2} > S r F_{2}$ .
Ionic order $L i C l < N a C l < K C l$ : so melting point order is same.
Order of thermal stability -
$B e S O_{4}, M g S O_{4}, C a S O_{4}, S r S O_{4}, B a S O_{4} - ---------------------------- \to Ionic nature increases, Thermal stability increaes$

Suggest Corrections

Similar questions

B a S O_{4} > S r S O_{4} > C a S O_{4} > M g S O_{4}

Z n O > B e O > M g O > C a O

L i O H > N a O H > K O H > R b O H

N a C l > K C l > R b C l > L i C l

B e S O_{4}, M g S O_{4}, C a S O_{4}, S r S O_{4}, B a S O_{4}

B e S O_{4}, M g S O_{4}, C a S O_{4}, S r S O_{4}

N a_{2} S O_{4}, B e S O_{4}, M g S O_{4}

B a S O_{4}

L i C l

N a C l

K C l

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