Choose the correct order of nucleophilicity

⊖ S C H_{3} > ⊖ S C H (C H_{3})_{2} > ⊖ S C (C H_{3})_{3}

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⊖ S C H_{3} < ⊖ S C H (C H_{3})_{2} < ⊖ S C (C H_{3})_{3}

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⊖ S C H (C H_{3})_{2} < ⊖ S C (C H_{3})_{3} < ⊖ S C H_{3}

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⊖ S C (C H_{3})_{3} = ⊖ S C H_{3} = ⊖ S C H (C H_{3})_{2}

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Solution

The correct option is A $⊖ S C H_{3} > ⊖ S C H (C H_{3})_{2} > ⊖ S C (C H_{3})_{3}$
A reagent which donates an electron pair to an electron deficient centre (except $H^{+}$ ) is called as nucleophile.
Nucleophilicity implies how good/fast a species is at reacting site.
$Nucleophilicity \propto \frac{1}{steric hinderance}$
$⊖ S C (C H_{3})_{3}$ has more steric hinderance due to presence of 3 methyl group followed by $⊖ S C H (C H_{3})_{2}$ which has only 2 methyl group.
$⊖ S C H_{3}$ being less hindered is more nucleophilic.
The correct order of nucleophilicity order is
$⊖ S C H_{3} > ⊖ S C H (C H_{3})_{2} > ⊖ S C (C H_{3})_{3}$

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