Choose the correct order of reactivity toward nucleophilic substitution:

(I) < (II) < (III)

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(I) < (III) < (II)

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(III) < (II) < (I)

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(II) < (III) < (I)

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Solution

The correct option is C (II) < (III) < (I)
$C H_{3}$ group decrease the reactivity of the compound towards nucleophilic substitution reaction due to its +I effect the compound becomes electron-rich.

The reactivity of the compound depends upon the position of the methyl group. Hence the reactivity order w.r.t the position of methyl group is:
$M e t a - > O r t h o -$

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