Choose the correct order(s) of basic strengths of given amines in gaseous phase.

(C_{3} H_{7})_{3} N > (C_{3} H_{7})_{2} N H > C_{3} H_{7} N H_{2} > N H_{3}

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(C H_{3})_{3} N > (C H_{3})_{2} N H > C H_{3} N H_{2} > N H_{3}

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(C_{2} H_{5})_{3} N > (C_{2} H_{5})_{2} N H > C_{2} H_{5} N H_{2} > N H_{3}

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(C_{2} H_{5})_{2} N H > (C_{2} H_{5})_{3} N > C_{2} H_{5} N H_{2} > N H_{3}

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Solution

The correct option is C $(C_{2} H_{5})_{3} N > (C_{2} H_{5})_{2} N H > C_{2} H_{5} N H_{2} > N H_{3}$
In gaseous phase, the basic strength of the amines is based on the number of +I groups present in the compound. Higher the number of +I group, greater will be the basic strength of the compound. We know alkyl groups are +I groups. Hence, tertiary amines are more basic than secondary and they are more basic than primary amines.
So the decreasing order of basic strength of amines in gaseous phase follows the order,
$3^{o} > 2^{o} > 1^{o} > N H_{3}$
So here the option (d) is wrong.

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