Choose the correct reaction to prepare mercurous chloride (calomel):

H g {C l}_{2} + H g Δ - \to

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H g + {C l}_{2} ⟶

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H g {C l}_{2} + S n {C l}_{2} ⟶

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Both options (a) and (c)

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Solution

The correct option is D Both options (a) and (c)
Mercurous chloride (calomel) is prepared by heating $H g {C l}_{2}$ and $H g$ in iron vessel.

$H g {C l}_{2} + H g Δ - \to {H g}_{2} {C l}_{2}$

It can also be prepared by the reduction of mercury (II) chloride by tin (II) chloride in a limited quantity.

$2 {H g} {C l}_{2} + S n {C l}_{2} ⟶ {H g}_{2} {C l}_{2} + S n {C l}_{4}$

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