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Electrochemical Series

Choose the co...

Question

Choose the correct shorthand notation for standard reduction potential of the given reactions.

$(a) H g_{2}^{2 +} (a q) + 2 e^{-} ⇌ 2 H g (l)$

$(b) F e^{3 +} (a q) + e^{-} ⇌ F e^{2 +} (a q)$

a. E_{H g_{2}^{2 +} (a q) / H g_{2} (l)}^{o}

b. E_{F e^{3 +} (a q) / F e (s)}^{\circ}

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a. E_{H g_{2}^{2 +} (a q) / H g (l)}^{o}

b. E_{F e^{2 +} (a q) / F e^{3 +} (a q)}^{\circ}

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a. E_{H g_{2}^{2 +} (a q) / H g (l)}^{o}

b. E_{F e^{3 +} (a q) / F e^{2 +} (a q)}^{\circ}

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a. E_{H g (l) / H g_{2}^{2 +} (a q)}^{o}

b. E_{F e^{2 +} (a q) / F e^{3 +} (a q)}^{\circ}

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Solution

The correct option is C $a. E_{H g_{2}^{2 +} (a q) / H g (l)}^{o}$

$b. E_{F e^{3 +} (a q) / F e^{2 +} (a q)}^{\circ}$
Electrode potential for reduction half reaction is called reduction potential. The corresponding electrode is termed as positive electrode.

Here, $H g_{2}^{2 +}$ and $F e^{3 +}$ gets reduced to $H g$ and $F e^{2 +}$ respectively.

Thus, shorthand notation for standard reduction potential of the given reactions are
$a. E_{H g_{2}^{2 +} (a q) / H g (l)}^{o}$

$b. E_{F e^{3 +} (a q) / F e^{2 +} (a q)}^{\circ}$

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Similar questions

298 K

{Z n}^{2 +} (a q) + 2 e^{-} ⇌ Z n (s) - 0.762

{C r}^{3 +} (a q) + 3 e^{-} ⇌ C r (s) - 0.74

2 H^{+} (a q) + 2 e^{-} ⇌ H_{2} (g) + 0.00

{F e}^{3 +} (a q) + e^{-} ⇌ {F e}^{2 +} (a q) + 0.77

Z n^{2 +} (a q) + 2 e^{-} ⇌ Z n (s);

- 0.762 V

C r^{3 +} (a q) + 3 e^{-} ⇌ C r (s);

- 0.74 V

2 H^{+} (a q) + 2 e^{-} ⇌ H_{2} (g);

+ 0.00 V

F e^{3 +} (a q) + e^{-} ⇌ F e^{2 +} (a q);

+ 0.77 V

(a) C H_{3} C O O^{-} (a q) + 4 H_{2} O (a q) ⇌ 2 H C O_{3}^{-} (a q) + 9 H^{+} (a q) + 8 e^{-}

(b) C (s) + 2 H_{2} O (a q) ⇌ C O_{2} (a q) + 4 H^{+} (a q) + 4 e^{-}

25^{o}

Z n^{2 +} (a q) + 2 e^{-} ⇌ Z n (s), - 0.76

C r^{3 +} (a q) + 3 e^{-} ⇌ C r (s), - 0.74

2 H^{+} (a q) + 2 e^{-} ⇌ H_{2} (g), + 0.0

F e^{3 +} (a q) + e^{-} ⇌ F e^{2 +} (a q), 0.77

Z n^{2 +} (a q) + 2 e^{-} ⇌ Z n (s); E^{o} = - 0.762 V

C r^{3 +} (a q) + 3 e^{-} ⇌ C r (s); E^{o} = + 0.762 V

2 H^{+} (a q) + 2 e^{-} ⇌ H_{2} (g); E^{o} = + 0.00 V

F e^{3 +} (a q) + e^{-} ⇌ F e^{2 +} (a q); E^{o} = + 0.770 V

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