Choose the correct statement regarding the product of reaction between silver nitrate and sodium thiosulphate.

Compound formed is unstable at high temperature.

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

On warming the solution we get

A g_{2} S

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Compound formed is yellow precipitate.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Precipitate formed is soluble in excess of thiosulphate solution.

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct options are
A On warming the solution we get $A g_{2} S$
B Precipitate formed is soluble in excess of thiosulphate solution.
C Compound formed is unstable at high temperature.
$2 A g N O_{3} + N a_{2} S_{2} O_{3} ⟶ A g_{2} S_{2} O_{3} ↓ + 2 N a N O_{3}$
$A g_{2} S_{2} O_{3}$ is unstable at high temperature.
$A g_{2} S_{2} O_{3} ⟶ A g_{2} S ↓ + S O_{3} ↑$
$A g_{2} S_{2} O_{3} + S_{2} O_{3}^{2 -} + S_{2} O_{3}^{2 -} ⟶ [A g (S_{2} O_{3})_{2}]^{- 3}$

Suggest Corrections

Similar questions

The following equation represents double displacement reaction, what is the precipitate formed in this reaction?

$A g N O_{3} (a q) + N a I (a q) \to A g I (s) + N a N O_{3} (a q)$

Join BYJU'S Learning Program