The correct option is D Function f(t) = e−kt is not periodic.
Statement (a) is correct. The function f (t) = sin kt + cos kt can be written as f(t)=√2 sin(kt+π4)or√2cos (kt−π4)
both of which are simple harmonic. The coefficient of time t in the argument of the sine or cosine function = 2πT where T is the period. Hence k =2πTorT=2πk
Statement (b) is also correct. Each term represents simple harmonic motion. The period T of term sin πt is π = 2πT or T = 2s. The period of term 2 cos 2πt is 1s, i.e., T/2 and the period of term 3 sin 3 πt is 2/3 s, i.e, T/3. The sum of two or more simple harmonic motions of different periods is not simple harmonic. The sum, however, is periodic. By the time the first term completes one cycle, the second term completes two cycles and the third term completes three cycles. Thus the sum has a period of 2s. Statement (c) is incorrect. We can write
f(t)=cos kt+2 sin2ktf(t)=cos kt+(1−cos 2kt)=1+cos kt−cos 2kt
The period of cos kt is T = 2πT and of cos 2k is πT which is T/2. As explained above, the periodof the two terms together is T = 2πT. The term 1 is a constant independent of time. Statement (d) is correct. Function e−kt decreases monotonically to zero it never becomes negative. Hence it is non-periodic.