Choose the correct statement(s) regarding a first order reaction :
Here, t12 is the half life period for first order reaction k is the first order rate constant
A
The graph between t12 (y-axis) and initial concentration of reactant (x-axis) is a straight line parallel to x-axis
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B
The graph between t12 y-axis) and initial concentration of reactant (x-axis) is a rectangular hyperbola
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C
t12=ln2k
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D
t12=[A]02k
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Solution
The correct option is Ct12=ln2k Since [A]=[A]0e−kt
Here [A]0 is the intial concentration. [A] is the concentration at time t
Now, at t=t12,[A]=[A]02
Putting the value in equation: [A]02=[A]0e−kt12
Solving, t12=ln2k
The graph between t12(y−axis)and concentration of reactant (x-axis )is a straight line parallel to x axis as shown: