wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Choose the correct values of wavelength and frequency of a light wave whose time period is 2×1010 s.

A
Frequency = 5×109 s1,
wavelength = 6×102 m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Frequency = 5×109 s1,
wavelength = 2×102 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Frequency = 1.67×109 s1,
wavelength =6×102 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Frequency = 5×103 s1,
wavelength =6×102 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A Frequency = 5×109 s1,
wavelength = 6×102 m
Given: Time period = 2×1010s
Now, frequency =1time period=12×1010s=5×109s1.

Using relation between wavelength and frequency: λ=cv
where,
λ= wavelength of the radiation
c = speed of light
v = frequency of the wave

λ=3×1085×109=6×102 m

flag
Suggest Corrections
thumbs-up
3
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Wave Nature of Light
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon