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Question

Choose the correct values of wavelength and frequency of a light wave whose time period is 2×1010 s.

A
Frequency = 5×109 s1,
wavelength = 6×102 m
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B
Frequency = 5×109 s1,
wavelength = 2×102 m
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C
Frequency = 1.67×109 s1,
wavelength =6×102 m
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D
Frequency = 5×103 s1,
wavelength =6×102 m
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Solution

The correct option is A Frequency = 5×109 s1,
wavelength = 6×102 m
Given: Time period = 2×1010s
Now, frequency =1time period=12×1010s=5×109s1.

Using relation between wavelength and frequency: λ=cv
where,
λ= wavelength of the radiation
c = speed of light
v = frequency of the wave

λ=3×1085×109=6×102 m

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