The correct option is A $100 and $150
Let the cost of each chair is x and that of each table is y,
Given,
The cost of two tables and three chairs is $600.
∴3x+2y=600 …(i)
and the table costs $50 more than the chair
∴y=x+50…(ii)
Step 1: Find the value of x
Substituting y=x+50 in (i), we get
Equation (i) → 3x+2y=600
3x+2(x+50)=600
⇒3x+2x+100=600⇒5x=600−100=500⇒x=5005⇒x=100
Step 2: Now, Find the value of y
Substitute x=100 in equation (ii)
Equation (ii) → y=x+40
y=100+50
⇒y=150
∴x=100,y=150
Therefore, the cost of each chair is $100 and that of each table is $150.