The correct option is D 2Na+2H2O→2NaOH+H2
The H+ ion in water get reduced from +1 to 0 oxidation state and liberate as H2 gas.
Hence in option (a), (b) and (d) H2 is produced hence it shows that H+ is reduced. Thus water is a oxidising agent.
In option (c), the OH− ion of water get oxidise from -2 to 0 oxidation and liberate as O2 gas. Hence in option(c) water is acts as a reducing agent, it reduced F2 to F−.
Hence option (a), (b) and (d) are correct.