The correct option is D CXCIX
We know that I = 1, V =5, X = 10, L = 50 and C = 100.
Also, when a Roman numeral with the larger value is on the left, we add the values together and when it is on the right, we subtract the values.
∴ CLI = 100 + 50 + 1 = 151
CXL = 100 + (50 - 10) = 150 - 10 = 140
CLXIX = 100 + 50 + 10 + (10 - 1)
= 170 - 1
= 169
CXCIX = 100 + (100 - 10) + (10 - 1) = 199
Since 140<151<169<199, we have CXCIX is the largest among the given options.