Question

Choose the largest number among the following.

• A. 123
• B. 896
• C. 769
• D. 899

Answer 1

The correct option is D 899

Since the numbers given have the same number of digits, we compare the place value of individual digits.

$\begin{array}{cc}\text{Number}& \text{Number of hundreds}\\ \underset{–}{1}23& 1\\ \underset{–}{8}96& 8\\ \underset{–}{7}69& 7\\ \underset{–}{8}99& 8\end{array}$

Since 8 is greater than 1 and 7, we have 896 and 899 both to be greater than 123 and 769. We now need to compare 896 and 899.

Comparing digits at tens place:

$\begin{array}{cc}\text{Number}& \text{Number of tens}\\ 8\underset{–}{9}6& 9\\ 8\underset{–}{9}9& 9\end{array}$

Since 899 and 896 both have 9 tens, we compare the digits at the ones place.

$\begin{array}{cc}\text{Number}& \text{Number of ones}\\ 89\underset{–}{6}& 6\\ 89\underset{–}{9}& 9\end{array}$

Since 9 is greater than 6, 899 is greater than 896.

Thus, 899 is the greatest of the lot.