Choose the most appropriate option. 'A' and 'B' complete a work in 12 days, 'B' and 'C' in 8 days and 'C' and 'A' in 16 days. 'A' left after working for 3 days. In how many days more will 'B' and 'C' finish the remaining work?
A
734
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B
656
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C
434
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D
334.
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Solution
The correct option is B434 A and B complete a work in 12 days
A and B complete a work in 1 day,
⇒A+B=112 ----- ( 1 )
B and C complete a work in 8 days
B and C complete a work in 1 day,
⇒B+C=18 ----- ( 2 )
C and A complete a work in 16 days
C and A complete a work in 1 day,
⇒A+C=116 ----- ( 3 )
Solving equation ( 2 ) and ( 3 ), we get
⇒B−A=116 ----- ( 4 )
Solving equation ( 1 ) and ( 4 ) we get,
B=796 and A=196
Assuming A and B and C start the work.
If A and B+C works for 3 days, work completed in 1 day is
⇒18+196=1396
Work in 3 days =1396×3=1332
Balance work is done in 1 day, how many days to complete 1932th work =1932×8