Question

Choose the numbers which are completely divisible by $3$?

• A. $966$
• B. $777$
• C. $225$
• D. 252

Answer 1

Answer: (A), (B), (C), (D)

252

For a number to be divisible by $3$ sum of digits of that number should be divisible by $3$.

$966\to 9+6+6=21$, here 21 is divisible by 3

$777\to 7+7+7=21$, here 21 is divisible by 3

$225\to 2+2+5=9$, here 9 is divisible by 3.

$252\to 2+5+2=9$, here 9 is divisible by 3.

In above question all numbers have sum of digits divisible by $3$.
So, all numbers are divisible by $3$.