Question

Choose the odd one out:

$\left(1\right)$ $145$
$\left(2\right)$ $120$
$\left(3\right)$ $90$
$\left(4\right)$ $105$

• A. $145$
• B. $120$
• C. $90$
• D. $105$

Answer 1

The correct option is A $145$

Except $145$ all are divisible by $3$
Divisibility test by $3\to$ Sum of all the digits should be divisible by $3$
$\left(A\right)$ $145\to (1+4+5=10)$.....(Not divisible by 3)
$\left(B\right)$ $120\to (1+2+0=3)$.....(Divisible by 3)
$\left(C\right)$ $90\to (9+0=9)$.....(Divisible by 3)
$\left(D\right)$ $105\to (1+0+5=6)$.....(Divisible by 3)
Hence, option $A$ is the correct answer.