Question

Choose the possible word problem for the given expression. $\frac{1}{5}÷4$

• A. Shirley has made four cheese pizzas and $\frac{1}{5}\text{lb}$ of cheese is required to make one pizza. Find the total mass of cheese used to make the pizzas.
  
• B. If $\frac{1}{5}\text{lb}$ of cheese is used to make four pizzas. How much cheese is used for each pizza?
  
• C. $\frac{1}{5}\text{lb}$ of cheese is required to make one pizza. How many pizzas can be made with $4\text{lb}$ of cheese?
  
• D. $\frac{1}{5}\text{lb}$ of cheese is required to make one pizza. Find the total mass of cheese required to make $20$ pizzas.

Answer 1

The correct option is B If $\frac{1}{5}\text{lb}$ of cheese is used to make four pizzas. How much cheese is used for each pizza?



The fraction is $\frac{1}{5}$
$\frac{1}{5}$ is divided into 4 parts.
So, $\frac{1}{5}÷4$ = $\frac{1}{20}$
Total amount of cheese $=\frac{1}{5}\text{lb}$
Number of pizzas $=4$
Amount of cheese required for each pizza = Total amount of cheese ÷ Number of pizzas
$=\frac{1}{5}÷4$
This expression gives us the answer to the amount of cheese to divide $\frac{1}{5}\text{lb}$ of cheese equally for $4$ pizzas.

Option A:
Total number of pizzas $=4$
Cheese required for one pizza $=\frac{1}{5}\text{lb}$
Total Mass of cheese required for four pizzas $=4\times \frac{1}{5}\text{lb}$
Option A does not satisfy the given expression.

Option B:
Total amount of cheese $=4\text{lb}$
Cheese required for one pizza $=\frac{1}{5}\text{lb}$
Number of pizzas can be made = Total amount of cheese $÷$ Cheese required for one pizza
$=4÷\frac{1}{5}$
So, Option B does not match the given expression.

Option C:
Total cheese $=\frac{1}{5}\text{lb}$
Number of pizzas $=4$
Cheese on each pizza = Total cheese $÷$ number of pizzas
$=\frac{1}{5}÷4$
Option C matches with the given expression.


Option D:
Cheese required for one pizza $=\frac{1}{5}\text{lb}$
Number of pizzas $=20$
Total amount of cheese = Cheese required for one pizza $\times$ Number of pizzas
$=\frac{1}{5}\times 20$
Option D does not match with the given expression.
Hence, Option C is correct.