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Position of a Point with Respect to a Circle

Choose the ri...

Question

Choose the right option based on the image below.

A

OP < OA < OQ

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B

OQ < OA > OP

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C

OQ > OP > OA

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D

OP = OA = OQ

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Solution

The correct option is A OP < OA < OQ
OA is the radius of the circle. P lies inside the circle and Q lies outside the circle. Hence OP < radius and OQ > radius.
Thus, the correct order is: OP < OA < OQ.
Hence, option A is correct.

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Similar questions

$In the given figure, OA = OB and OP = OQ. Prove that (i) PX = QX, (ii) AX = BX.$

\to O A

\to O B

are two vectors such that

∣ ∣ \to O A + \to O B ∣ ∣

∣ ∣ \to O A + \to 2 O B ∣ ∣ .

Q. Draw four lines

O A, O B, O C, O D

∠ A O B = 48^{o}

∠ C O D = 34^{o}

O P

∠ A O B

O Q

∠ C O D

O Q

is perpendicular to

O P

∠ B O C

.

Q. The value of

λ

so that the points

P, Q, R, S

O A, O B, O C

A B

of a regular tetrahedron are co-planar when

\frac{O P}{O A} = \frac{1}{3}; \frac{O Q}{O B} = \frac{1}{2}; \frac{O R}{O C} = \frac{1}{3}

\frac{O S}{A B} = λ

Q. Find the value of

λ

so that the points

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S

O A, O B, O C

A B

respectively of a regular tetrahedron

O A B C

are coplanar. It is given that

\frac{O P}{O A} = \frac{1}{3}, \frac{O Q}{O B} = \frac{1}{2}

\frac{O S}{A B} = λ

.

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