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Question

Choose the set of coefficients that correctly balances the following equation :
xCr2O27+yH++zeaCr+3+bH2O
x y z a b
1) 2 14 6 2 7
2) 1 14 6 2 7
3) 2 7 6 2 7
4) 2 7 6 1 7

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Solution

Here we have to use try & error methods:-
Considering option 2) x=1y=14z=6a=2b=7 equation is
Cr2O27+14H+6e2cr+3+7H2O
Right hand side
No of cr atoms =2
No of O atoms =7
No of H atoms =14
Total charge =(2)+(6)+14
+6
Left hand side
No of cr atom =2
No of O atoms =7
No of H atoms =14
Total charge 2(+3)
+6

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