Choose the set of coefficients that correctly balances the following equation :
$x {C r}_{2} O_{7}^{2 -} + y H^{+} + z e^{-} \to a {C r}^{+ 3} + b H_{2} O$
x y z a b
1) 2 14 6 2 7
2) 1 14 6 2 7
3) 2 7 6 2 7
4) 2 7 6 1 7

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Solution

Here we have to use try & error methods:-
Considering option 2) $x = 1 y = 14 z = 6 a = 2 b = 7$ equation is
$C r_{2} O_{7}^{- 2} + 14 H^{+} 6 e^{-} \to 2 c r^{+ 3} + 7 H_{2} O$
Right hand side
No of cr atoms = $2$
No of O atoms = $7$
No of H atoms = $14$
Total charge $= (- 2) + (- 6) + 14$
$+ 6$
Left hand side
No of cr atom $= 2$
No of O atoms $= 7$
No of H atoms $= 14$
Total charge $2 (+ 3)$
$+ 6$

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