Question

Choose the wrong statement

a) Work done in moving a charge on equipotential surface is zero.

b) Electric lines of force are always normal to equipotential surface.

c) When two like charges are brought nearer, then electrostatic potential energy of the system is decreased.

d) Electric lines of force diverge at positive charge and converge towards negative charge.

• A. a
• B. b
• C. c
• D. d

Answer 1

The correct option is C c

a ) On equipotential surface voltage remains constant,

$\therefore$ no work is required to move the charge.
b ) Electric lines of forces are always normal to equipotential surface.
c ) When two $+ve$ charges are brought together, we know potential energy is given by $U=\frac{k{q}_1{q}_2}{r}$
$\therefore$ for two positive charges, $U\propto \frac{1}{r}$ when r decreases U increases.