Chords AB & CD (not the diameters) of a circle intersect at point P inside the circle.
Find the sum of the angles subtended at the centre of the circle by the arcs AC & BD in terms of ∠APC.
∠APC
1.2∠APC
1.5∠APC
1.8∠APC
2∠APC
In the given figure, AB and CD are two chords of a circle, intersecting each other at a point E. Prove that ∠AEC=12(angle subtended by arc CXA at the centre + angle subtended by arc DYB at the centre).
O is the centre of the circle. AB is a minor arc of the circle. The angle subtended by AB at centre, ∠AOB = 110∘, then angle subtended by the arc at any point on the circle say ∠APB is ____, where P is any point on the circle.