wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Chords AB & CD of a circle are parallel to each other and lie on opposite sides of the centre of the circle. If AB = 36 cm, CD = 48 cm and the distance between the chords is 42 cm. Find the radius of the circle.


A

24 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

30 cm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

38 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

40 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

30 cm


In ΔEOB, r2 = (42x)2+ (18)2 ------ (i)

In ΔFOD, r2 = (24)2 +x2 ------ (ii)

Subtract (i) from (ii), we get

(42x)2+(18)2=(24)2+ x2

(42x)2x2=(24)2(18)2

(42- 2x)(42) = 6×(42)

x = 18 cm

Putting the value of x in equation (ii), we get

r2=(18)2+(24)2

r = 30 cm


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Circles and Their Chords - Theorem 7
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon