Chromyl chloride test is performed for the confirmation of the presence of the following in mixture :

S O_{4}^{2 -}

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C r^{3 +}

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C l^{-}

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C r^{3 +}

and

C l^{-}

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Solution

The correct option is B $C l^{-}$
When a mixture containing chloride ion is heated with $K_{2} C r_{2} O_{7}$ and concentrated $H_{2} S O_{4}$ , deep orange-red fumes of chromyl choloride $(C r O_{2} C l_{2})$ are formed.
$K_{2} C r_{2} O_{7} + 4 N a C l + 6 H_{2} S O_{4} \to 2 K H S O_{4} + 4 N a H S O_{4} + 2 C r O_{2} C l_{2} O r a n g e - r e d f u m e s ↑ + 3 H_{2} O$

When chromyl chloride vapours are passed into sodium hydroxide solution, a yellow solution of sodium chromate is formed, which when treated with lead acetate gives yellow precipitate of lead chromate.
$C r O_{2} C l_{2} ↑ + 2 N a O H \to N a_{2} C r O_{4} Y e l l o w s o l u t i o n + 2 H C l$

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Similar questions

{C l}^{-}

E_{C l_{2} / C l^{-}}^{\circ} = 1.36 V, E_{C r^{3 +} / C r} = - 0.74 V

E_{C r_{2} O_{7}^{2 -} / C r^{3 +}} = 1.33 V, E_{M n O_{4}^{-} / M n^{2 +}}^{\circ} = 1.51 V

E_{C l_{2} / C l^{-}}^{o} = 1.36 V, E_{C r^{3 +} / C r}^{\circ} = - 0.74 V

E_{C r_{2} O_{7}^{2 -} / C r^{3 +}}^{o} = 1.33 V, E_{M n O_{4}^{-} / M n^{2 +}}^{o} = 1.51 V

(C r C l_{3})

C l^{-}

C r^{3 +}

E_{C l_{2} / C l^{-}}^{\circ} = 1.36 V, E_{C r^{3 +} / C r}^{\circ} = - 0.74 V E_{C r_{2} O_{7}^{2 -} / C r^{3 +}}^{\circ} = 1.33 V, E_{M n O_{4}^{-} / M n^{2 +}}^{\circ} = 1.51 V

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