Cinnabar ( $HgS$ ) is a prominent ore of mercury. How many grams of mercury are present in 225 g of pure $HgS$ ?
Molar mass of $Hg$ and $S$ are 200.6 g ${mol}^{- 1}$ and 32 g ${mol}^{- 1}$ respectively.

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Solution

We have
Molar mass of $Hg$ =200.6 g ${mol}^{- 1}$
Molar mass of $S$ =32 g ${mol}^{- 1}$
$M o l a r m a s s o f H g S = M o l a r m a s s o f H g + M o l a r m a s s o f S = 200.6 + 32 = 232.6 m o l^{- 1}$
Mass of Hg in 225 g of HgS $= \frac{200.6 H g \times \times 225}{232.6}$ =194.04 g

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