Circle drawn through the point (2,0) to cut intercept of length ‘5′ units on the x-axis. If its centre lie in the first quadrant then the equation of family of such circles is
The correct option is B. x2+y2−9x−2ky+14=0,k>0
AB=5
Centre =(2+72,K)
=(92,K)
Radius =√254+K2
Equation of circle is
(x−92)2+(y−k)2=254+k2
⇒x2+814−9x+y2+k2−2ky=254+k2
⇒x2−9x+y2−2ky+564=0
∴x2+y2−9x−2ky+14=0