Question

Circle on which the coordinates of any point are $(2+4\cos \theta ,-1+4\sin \theta )$ where $\theta$ is the parameter is given by $(x-2{)}^2+(y+1{)}^2=16$.

• A. True
• B. False

Answer 1

The correct option is A True

From given conditions, we have,

$x=2+4\cos \theta$

$x-2=4\cos \theta$ .......(1)

$y=-1+4\sin \theta$

$y+1=4\sin \theta$ .......(2)

Squaring and adding equation 1 and 2, we get,

$(x-2{)}^2+(y+1{)}^2=16$.