Question

Circle the numbers which are divisible by $2$.

$4263851629713582875030$

Answer 1

Given numbers: $4263,8516,2971,35828$ and $75030$.

We know that a number is divisible by $2$, if the digit at the ones place is an even digit, i.e., the digit at the ones place is $0,2,4,6$ or $8$.

So we can say, the numbers $8516,35828$ and $75030$are divisible by $2$.

Hence, $4263\overline{)8516}2971\overline{)35828}\overline{)75030}$.