Question

Circle the numbers which are divisible by $3$.

$81748060720135082$

Answer 1

Circle the numbers which are divisible by $3$.

Given numbers: $817,480,607,2013$ and $5082$.

We know that a number is divisible by $3$, if the sum of its digits is divisible by $3$.

So by calculating the sum of the digits of the given numbers separately we get,

$$\begin{gathered} 8+1+7=16 \\ 4+8+0=12 \\ 6+0+7=13 \\ 2+0+1+3=6 \\ 5+0+8+2=15 \end{gathered}$$

As $12,6$ and $15$ are divisible by $3$.

So we can say the numbers $480,2103$ and $5082$are divisible by $3$.

Hence, $817\overline{)480}607\overline{)2013}\overline{)5082}$.