Circular blanks of 35mm dia are punched from a steel sheet of 2mm thickness, If the clearance per side between the punch and die is to be kept as 40 microns. The size of punch and die should respectively be
A
35 and 835.040
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B
34.92 and 35
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C
35 and 35.080
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D
35.040 and 34.92
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Solution
The correct option is B34.92 and 35 Diameter of blank = Diameter of die
Diameter of die =35mm
Clearance =0.04mm per side
Total clearance =0.04×2=0.08mm
Diameter of punch = Diameter of die - Clearance =35−0.08=34.92mm