Circumcentre of the triangle formed by the line y = x, y = 2x and y = 3x + 4 is
(6, 8)
(6, - 8)
(3, 4)
(- 3, - 4)
x2+y2=(x+4)2+(y+8)2 ⇒ 8x + 16y + 80 = 0
and x2+y2=(x+2)2+(y+2)2 ⇒ 4x + 4y + 8 = 0
On simplification, we get y = -8 and x = 6.