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Question

Circumcentre of the triangle formed by the line y = x, y = 2x and y = 3x + 4 is


A

(6, 8)

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B

(6, - 8)

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C

(3, 4)

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D

(- 3, - 4)

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Solution

The correct option is B

(6, - 8)


x2+y2=(x+4)2+(y+8)2 8x + 16y + 80 = 0

and x2+y2=(x+2)2+(y+2)2 4x + 4y + 8 = 0

On simplification, we get y = -8 and x = 6.


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