Cis-trans isomerism is found in square planar complexes of the molecular formula: (a and b are monodentate ligands)

M a_{4}

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M a_{3} b

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M a_{2} b_{2}

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M a b_{3}

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Solution

The correct option is C $M a_{2} b_{2}$
For square planar complexes $M a_{4}, M a_{3} b$ or $M a b_{3}$ where $a$ and $b$ etc, are monodentate ligands, again the geometrical isomerism is not possible. However, sequare planar cpmplexes of the type $M a_{2} b_{2}, M a_{2} b c, M a b c d$ and $M (A A)_{2}, M (A B)_{2}$ where $A A$ and $A B$ represent symmetrical and unsymmetrical chelating agents - do give geometrical isomers. A few examples are given below.

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