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Limiting Reagent or Reactant

Cl2g+2Br-exce...

Question

${C l}_{2} (g) + 2 {B r}^{-} (e x c e s s) ⟶$
When $1$ mole of chlorine gas reacts completely with excess $K B r$ solution, as shown above, the products obtained are :

1

mole of

{C l}^{-}

ions and

1

mole of

B r_{2}

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1

mole of

{C l}^{-}

ions and

2

moles of

B r_{2}

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2

mole of

{C l}^{-}

ions and

2

mole of

B r_{2}

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2

moles of

{C l}^{-}

ions and

1

mole of

B r_{2}

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2

moles of

{C l}^{-}

ions and

4

moles of

B r_{2}

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Solution

The correct option is D $2$ moles of ${C l}^{-}$ ions and $1$ mole of $B r_{2}$
When 1 mole of chlorine gas reacts completely with excess $K B r$ solution, as shown above, the products obtained are 2 moles of $C l^{-}$ ions and 1 mole of $B r_{2}$ .
${C l}_{2} (g) + 2 {B r}^{-} (e x c e s s) ⟶ 2 {C l}^{-} (a q) + {B r}_{2} (g)$

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Cl2(g)+2Br−(excess)⟶When 1 mole of chlorine gas reacts completely with excess KBr solution, as shown above, the products obtained are :

The correct option is D 2 moles of Cl− ions and 1 mole of Br2 When 1 mole of chlorine gas reacts completely with excess KBr solution, as shown above, the products obtained are 2 moles of Cl− ions and 1 mole of Br2.Cl2(g)+2Br−(excess)⟶2Cl−(aq)+Br2(g)

${C l}_{2} (g) + 2 {B r}^{-} (e x c e s s) ⟶$
When $1$ mole of chlorine gas reacts completely with excess $K B r$ solution, as shown above, the products obtained are :