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Question

Cl2(g)+OH(aq)OCl(aq)+Cl(aq)
Balance the above reaction using oxidation number method.

A
3Cl2(g)+5OH(aq)OCl(aq)+Cl(aq)+2H2O(l)
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B
Cl2(g)+2OH(aq)OCl(aq)+Cl(aq)+H2O(l)
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C
2Cl2(g)+2OH(aq)OCl(aq)+6Cl(aq)+H2O(l)
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D
2Cl2(g)+OH(aq)5OCl(aq)+Cl(aq)+3H2O(l)
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Solution

The correct option is B Cl2(g)+2OH(aq)OCl(aq)+Cl(aq)+H2O(l)
0Cl2(g)+OH(aq)O+1Cl(aq)+1Cl(aq)


nf=(|O.S.ProductO.S.Reactant|)×number of atom

(nf)OCl=|+10|×1=1
(nf)Cl=|10|×1=1

Cross multiplying with nf values.

Cl2(g)1 OCl(aq)+1 Cl(aq)

Elements except O and H are already balanced.

Now, balancing oxygen by adding H2O

Cl2(g)+H2O(l)OCl(aq)+Cl(aq)

Balancing hydrogen by adding H+
Cl2(g)+H2O(l)OCl(aq)+Cl(aq)+2H+(aq)

For balancing in basic medium adding 2OH to both sides
Cl2(g)+H2O(l)+2OH(aq)OCl(aq)+Cl(aq)+2H+(aq)+2OH(aq)

Cl2(g)+H2O(l)+2OH(aq)OCl(aq)+Cl(aq)+2H2O(l)

Canceling H2O
Cl2(g)+2OH(aq)OCl(aq)+Cl(aq)+H2O(l)

Balancing charge:

charge in reactant side =2=2
charge in product side =11=2

So the balanced equation is
Cl2(g)+2OH(aq)OCl(aq)+Cl(aq)+H2O(l)

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