${C l}_{2} + I O_{3}^{⊖} ⟶ {C l}^{⊖} + I O_{4}^{⊖}$ (in basic medium)

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Solution

The balanced redox reaction is as follows:
${C l}_{2} + I O_{3}^{⊖} + 2 ⊖ O H ⟶ 2 {C l}^{⊖} + I O_{4}^{⊖} + H_{2} O$

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Similar questions

{C l}_{2} + I O_{3}^{-} + {O H}^{-} ⟶ I O_{4}^{-} + {C l}^{-}

C l_{2} + {I O_{3}}^{-} + O H^{-} \to {I O_{4}}^{-} + C l^{-} + H_{2} O

C l_{2} + {I O_{3}}^{-} + O H^{-} \to {I O_{4}}^{-} + C l^{-} + H_{2} O

I O_{3}^{-} + C l^{-} \to I_{2} + C l_{2}

I^{⊖}

M n O_{4}^{⊖}

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