Class Interval
0-10
10-20
20-30
30-40
40-50
Frequency
12
16
6
7
9

Find the mean of the given distribution.

22

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18

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25

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9

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Solution

The correct option is A $22$
We first find the class mark by using the formula,
Class Mark $(x_{i}) = \frac{(L o w e r l i m i t + U p p e r l i m i t)}{2}$
From the table, we have
$Σ x_{i} f_{i} = 1100 & Σ f_{i} = 50$
Mean $= \frac{Σ x_{i} f_{i}}{Σ f_{i}} = \frac{1100}{50} = 22$
Hence, option A is correct.

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Similar questions

Class Interval	Frequency
0 - 10 10 - 20 20 - 30 30 - 40 40 - 50	4 6 10 16 14

Class interval	0-10	10-20	20-30	30-40	40-50	50-60	60-70
Frequency	2	3	x	6	5	3	2

Class-intervals	0-10	10-20	20-30	30-40	40-50
Frequency	12	11	14	10	13

Class	0-10	10-20	20-30	30-40	40-50
Frequency	7	15	13	17	10

Class	0-10	10-20	20-30	30-40	40-50
$f$	6	10	13	7	4

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