Class Interval
0-6
6-12
12-18
18-24
24-30
Frequency
6
8
10
9
7
If mean of above distribution is $15.45$ , If true then enter $1$ and if false then enter $0$

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Solution

$F o r g r o u p e d d a t a w h e n C l a s s I n t e r v a l i s g i v e n, w e f i n d t h e C l a s s M a r k . C l a s s M a r k = m i d p o i n t o f a n i n t e r v a l = \frac{(L o w e r l i m i t + U p p e r l i m i t)}{2} C l a s s M a r k i s t a k e n a s x_{i} f o r e a c h c l a s s i n t e r v a l . F i n d x_{i} f_{i} . F r o m t h e t a b l e, w e h a v e Σ x_{i} f_{i} = 618 & Σ f_{i} = 40 M e a n = \frac{Σ x_{i} f_{i}}{Σ f_{i}} = \frac{618}{40} = 15.45$

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Similar questions

14.4

20.

Class interval	0-6	6-12	12-18	18-24	24-30
Frequency	4	x	5	y	1

\begin{matrix} Class: & 0 - 6 & 6 - 12 & 12 - 18 & 18 - 24 & 24 - 30 Frequency : & a & b & 12 & 9 & 5 \end{matrix}

= \frac{309}{22}

= 14,

(a - b)^{2}

Class interval:	0-6	6-12	12-18	18-24	24-30
Frequency:	6	8	10	9	7

1

0

2 : 3

66 \frac{2}{3}

1

0

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