Class mark of a certain class interval is 30 and its lower class limit is 20. Then its upper class limit is

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Solution

The correct option is B
40

Class mark = $\frac{l o w e r c l a s s l i m i t + u p p e r c l a s s l i m i t}{2}$

$⟹ 30 = \frac{20 + u p p e r c l a s s l i m i t}{2}$

$⟹ (30 \times 2) - 20 = u p p e r c l a s s l i m i t$

$∴ u p p e r c l a s s l i m i t = 40$

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