Class mark of a particular class is 10.5, then upper limit + lower limit = _______.

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10.5

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Solution

The correct option is D 21
Class mark is always the value midway between the upper limit and the lower limit. In this case given that class mark is 10.5. Hence,

$\frac{u p p e r l i m i t + l o w e r l i m i t}{2}$ = 10.5

Hence upper limit + lower limit = $10.5 \times 2 = 21$ .

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Class mark of a particular class is 10.5, then upper limit + lower limit = _______.

The correct option is D 21Class mark is always the value midway between the upper limit and the lower limit. In this case given that class mark is 10.5. Hence, upperlimit+lowerlimit2 = 10.5 Hence upper limit + lower limit = 10.5×2=21.

The correct option is D 21
Class mark is always the value midway between the upper limit and the lower limit. In this case given that class mark is 10.5. Hence,

$\frac{u p p e r l i m i t + l o w e r l i m i t}{2}$ = 10.5

Hence upper limit + lower limit = $10.5 \times 2 = 21$ .