Class mark of a particular class is 9.5, then upper limit + lower limit = _______.

9.5

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Solution

The correct option is D 19
Class mark is always the value midway between the upper limit and the lower limit. In this case given that class mark is 9.5 . Hence

$\frac{u p p e r l i m i t + l o w e r l i m i t}{2}$ = 9.5

Hence, upper limit + lower limit = 9.5 x 2 = 19.

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Class mark of a particular class is 9.5, then upper limit + lower limit = _______.

The correct option is D 19Class mark is always the value midway between the upper limit and the lower limit. In this case given that class mark is 9.5 . Hence upperlimit+lowerlimit2 = 9.5 Hence, upper limit + lower limit = 9.5 x 2 = 19.

The correct option is D 19
Class mark is always the value midway between the upper limit and the lower limit. In this case given that class mark is 9.5 . Hence

$\frac{u p p e r l i m i t + l o w e r l i m i t}{2}$ = 9.5

Hence, upper limit + lower limit = 9.5 x 2 = 19.