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Byju's Answer
Standard XII
Mathematics
Median
Class0-1010-2...
Question
Class
0-10
10-20
20-30
30-40
40-50
Frequency
5
15
13
17
10
For the information given above
(
n
2
−
c
f
)
will be:
A
10
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B
20
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C
30
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D
25
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Solution
The correct option is
B
10
Class
Frequency
Cumulative - frequency
0
−
10
5
5
10
−
20
15
20
20
−
30
13
33
30
−
40
17
50
40
−
50
10
60
Therefore,
n
=
60
So,
n
2
=
60
2
=
30
∴
Median class is
20
−
30
∴
c.f
=
cumulative frequency preceding to the median class
=
20
∴
n
2
−
c
f
=
30
−
20
=
10
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0
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Q.
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n
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Q.
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Q.
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Q.
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