Question

Classify each of the following on the basis of their atomicity.

1. ${\mathrm{F}}_2$
2. ${\mathrm{NO}}_2$
3. ${\mathrm{N}}_2\mathrm{O}$
4. ${\mathrm{C}}_2{\mathrm{H}}_6$
5. ${\mathrm{P}}_4$
6. ${\mathrm{H}}_2{\mathrm{O}}_2$
7. ${\mathrm{P}}_4{\mathrm{O}}_{10}$
8. ${\mathrm{O}}_3$
9. $\mathrm{HCl}$
10. ${\mathrm{CH}}_4$
11. $\mathrm{He}$
12. $\mathrm{Ag}$

Answer 1

• The total number of atoms present in a molecule is called atomicity.

A molecule consisting of one atom is called a monoatomic.

Hence,

• $\mathrm{He}$ =1-Monoatomic
• $\mathrm{Ag}$ =1-Monoatomic

A molecule consisting of two atoms is called a diatomic.

Hence,

• ${\mathrm{F}}_2$= 2- Diatomic

A molecule consisting of three atoms is called triatomic

Hence,

• ${\mathrm{NO}}_2$= 3-Triatomic
• ${\mathrm{N}}_2\mathrm{O}$= 3- Triatomic
• ${\mathrm{O}}_3$ =3-Triatomic

A molecule that consists of more than four atoms is called a polyatomic molecule.

Hence,

• ${\mathrm{C}}_2{\mathrm{H}}_6$=8- Polyatomic
• ${\mathrm{P}}_4$ =5-- Polyatomic

• ${\mathrm{H}}_2{\mathrm{O}}_2$=4- Polyatomic
• ${\mathrm{P}}_4{\mathrm{O}}_{10}$= 14- Polyatomic
• ${\mathrm{CH}}_4$ =5-Polyatomic