Classify the following reaction- 2Mn O 4- - 5H2C2O4 - 6H- 2Mn2- - 10CO2 - 8H2O

The correct option is D Redox reactionThis is an oxidation reduction (redox) #160;reaction2MnO #8722;4+5H2C2O4+6H+ #8594;2Mn2++10CO2+8H2O ...

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Oxides of Phosphorus

Classify the ...

Question

Classify the following reaction.
$2 M n O_{4}^{-} + 5 H_{2} C_{2} O_{4} + 6 H^{+} \to 2 M n^{2 +} + 10 C O_{2} + 8 H_{2} O$

Acid-Base Neutralization reaction

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Combustion reaction

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Redox reaction

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Decomposition reaction

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Solution

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Similar questions

2 M n O_{4}^{-} + 16 H^{+} + 5 C_{2} O_{4}^{- 2} \to 2 M n^{2 +} + 8 H_{2} O + 10 C O_{2}

2 M n O_{4}^{-} + 5 C_{2} O_{4}^{2 -} + 16 H^{+} ⟶ 10 {C O}_{2} + 2 {M n}^{2 +} + 8 H_{2} O

O^{18}

2 M n O_{4}^{-} + 5 H_{2} O_{2}^{18} + 6 H^{+} \to 2 M n^{2 +} + 8 H_{2} O + 5 O_{2}

298 K

2 M n O_{4}^{-} + 6 H^{+} + 5 H_{2} C_{2} O_{4} \to 2 M n^{2 +} + 8 H_{2} O + 10 C O_{2} (E_{c e l l}^{\circ} = 2.0 V)

{2 m n O}_{4}^{-} + 6 H^{+} + {5 H}_{2} C_{2} O_{4} ⇌ {2 M N}^{2 +} + 8 H_{2} O + {10 C O}_{2}

E_{{M n O}_{4} M n^{2 +},}^{0} = 1.51 V

E_{{C O}_{3} C_{2} O_{4}^{2 -}}^{0} = - 0.49 V

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