Classify the following unbalanced half-reaction as either an oxidation or a reduction.

${C H}_{3} O H (a q) ⟶ {C H}_{2} O (a q)$

Oxidation

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Reduction

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Neither oxidation nor reduction

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None of these

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Solution

The correct option is A Oxidation
The unbalanced half reaction ${C H}_{3} O H (a q) ⟶ {C H}_{2} O (a q)$ is oxidation..
The oxidation number of C in ${C H}_{3} O H$ and ${C H}_{2} O$ is $- 2$ and $0$ respectively.
Thus, there is an increase in the oxidation number from reactant to product which indicates oxidation.
Hence, the correct option is A.

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