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Nucleophilic Substitution in Alkyl Halides

ClCH2CHCl2 AA...

Question

$C l C H_{2} C H C l_{2} alc. KOH - ---- \to A$
A is:

C H C l = C H C l

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C H_{2} = C C l_{2}

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C H \equiv C H

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C l C H_{2} C H O

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Solution

The correct option is B $C H_{2} = C C l_{2}$
Base will abstract the most acidic proton.

In alcoholic solution, elimination is favored. The most acidic hydrogen is removed in the elimination by base. Since it is not a strong base, it can not be further dehydrohalogenated.

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Similar questions

C l C H_{2} C H C l_{2} alc. KOH - ---- \to A

1)What is volume ?

2) What is magnitude?

3) What is density?

4) What is diffusion?

5)What is osmosis?

p : x

q : x^{2}

x

x^{2}

^{'} \div^{'}

^{'} +^{'}

^{'} \times^{'}

^{'} -^{'}

^{'} -^{'}

^{'} \div^{'}

^{'} +^{'}

^{'} \times^{'}

20 \div 4 \times 12 - 6 + 11

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