$C O_{2}$ concentration factor affecting photosynthesis process, which statement is correct for $C_{3}$ and $C_{4}$ plant?

X = 450 M L^{- 1}

Y = 350 M L^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

X = 360 M L^{- 1}

Y = 350 M L^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

X = 450 M L^{- 1}

Y = 360 M L^{- 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

X = 350 M L^{- 1}

Y = 450 M L^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $X = 450 M L^{- 1}$
$Y = 360 M L^{- 1}$
An increase in $C O_{2}$ concentration increases the rate of photosynthesis. But the higher concentration of $C O_{2}$ can inhibit the photosynthesis. In the atmosphere, there is 0.03-0.04% concentration of $C O_{2}$ . Increase in concentration up to 0.05% can increase the rate of photosynthesis. Beyond this level it becomes damaging. The $C_{3}$ plants show saturation at 450 ppm and the $C_{4}$ plants show saturation at 360 ppm of $C O_{2}$ concentration in the atmosphere.
So, the correct answer is C.

Suggest Corrections

Similar questions

(\frac{1}{x} + \frac{1}{y}) (\frac{1}{x} - \frac{1}{y}) = ?

(\frac{1}{x^{2}} - \frac{1}{y^{2}})

(\frac{1}{x^{2}} + \frac{1}{y^{2}})

(\frac{1}{x^{2}} + \frac{1}{y^{2}} - \frac{1}{x y})

(\frac{1}{x^{2}} - \frac{1}{y^{2}} + \frac{1}{x y})

1/3y+ y + 1/3x-y=3/4

1/2(3x+y)-1/2(3x-y)=-1/8

Solve for x and y

The product of all the factors of determinant

$∣ ∣ ∣ ∣ ∣ \begin{matrix} x & y & 1 x^{2} & y^{2} & 1 x^{3} & y^{3} & 1 \end{matrix} ∣ ∣ ∣ ∣ ∣$ is:

(1 - x^{2}) (1 - y^{2}) + 4 x y

Join BYJU'S Learning Program