$C O_{2}$ in water behaves as :

weak di-basic

H_{2} C O_{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

weak monobasic acid

H O - C O_{2} H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

weak diacid base

C O (O H)_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

weak monoacid base

H O - C O_{2} H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D weak di-basic $H_{2} C O_{3}$
$C O_{2}$ reacts with water and forms $C O_{2} + H_{2} O \to H_{2} C O_{3}$ , so in water it behaves as dibasic acid.

Suggest Corrections

Similar questions

C O_{2}

H_{3} O^{+}

H_{3} O^{+}

a q . N H_{3}

K_{a}

K_{b}

a q . N H_{3}

Join BYJU'S Learning Program